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    <title>Tool on Sebastian Spicker</title>
    <link>https://sebastianspicker.github.io/tags/tool/</link>
    <description>Recent content in Tool on Sebastian Spicker</description>
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      <title>Sebastian Spicker</title>
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      <title>Star Polygons and Drum Machines</title>
      <link>https://sebastianspicker.github.io/posts/tool-star-polygons-drum-machines/</link>
      <pubDate>Mon, 07 Jul 2025 00:00:00 +0000</pubDate>
      <guid>https://sebastianspicker.github.io/posts/tool-star-polygons-drum-machines/</guid>
      <description>The {7/2} heptagram is not only a symbol. It is a traversal algorithm over seven beat positions. Because 7 is prime, that traversal never gets trapped in a sub-orbit.</description>
      <content:encoded><![CDATA[<p>Two star polygons appear in Danny Carey&rsquo;s visual vocabulary, and they are not the same star. One is open, almost friendly — seven points connected by relatively shallow angles. The other is sharper, the points more acute. They look like variations on a theme, which is accurate: both are drawn on seven equally spaced vertices, but one connects every second vertex and the other connects every third.</p>
<p>In Schläfli notation — the system for naming regular star polygons — these are $\{7/2\}$ and $\{7/3\}$ <a href="#ref-1">[1]</a>. Both appear in Tool&rsquo;s artwork, in Thelemic symbolism, in medieval Islamic geometric patterns, and on the floor plans of cathedrals. They are the most visually intricate star polygons that can be drawn in a single closed stroke before the figure becomes illegible.</p>
<p>Both of them have a property that five-pointed and six-pointed stars do not share: they visit every vertex before closing. This is a consequence of 7 being prime. And it turns out to matter for how rhythmic accent cycles are built.</p>
<h2 id="the-schläfli-symbol">The Schläfli Symbol</h2>
<p>A regular star polygon $\{n/k\}$ is constructed by placing $n$ points evenly on a circle and connecting every $k$-th point in sequence until the path closes. The structural key is a single number:</p>
$$d = \gcd(n, k).$$<p>If $d = 1$, the traversal visits all $n$ vertices before returning to the start — a single connected figure. If $d > 1$, the path visits only $n/d$ vertices before closing, and the full figure consists of $d$ separate copies of the smaller star $\{(n/d)\,/\,(k/d)\}$.</p>
<p>The most familiar example of the disconnected case: $\{6/2\}$, the Star of David. Here $\gcd(6,2) = 2$, so the figure breaks into two copies of $\{3/1\} = \{3\}$ — two overlapping equilateral triangles. The traversal starting at vertex 1 visits $1 \to 3 \to 5 \to 1$, leaving vertices 2, 4, 6 entirely unvisited.</p>
<p>The pentagram $\{5/2\}$ is connected: $\gcd(5,2)=1$, traversal $1 \to 3 \to 5 \to 2 \to 4 \to 1$, all five vertices.</p>
<p>For $n=7$:</p>
<ul>
<li>$\{7/2\}$: $\gcd(7,2)=1$, traversal $1 \to 3 \to 5 \to 7 \to 2 \to 4 \to 6 \to 1$, all seven vertices.</li>
<li>$\{7/3\}$: $\gcd(7,3)=1$, traversal $1 \to 4 \to 7 \to 3 \to 6 \to 2 \to 5 \to 1$, all seven vertices.</li>
</ul>
<p>Both connected. Neither leaves any vertex unvisited.</p>
<h2 id="the-group-theory">The Group Theory</h2>
<p>The traversal of $\{n/k\}$ is an instance of a standard construction in modular arithmetic: the <strong>orbit</strong> of an element under repeated addition in $\mathbb{Z}/n\mathbb{Z}$.</p>
<p>Label the $n$ vertices $0, 1, \ldots, n-1$. Starting at vertex 0, the traversal visits:</p>
$$0, \quad k \bmod n, \quad 2k \bmod n, \quad 3k \bmod n, \quad \ldots$$<p>The orbit of 0 under the action of $+k$ is the subgroup of $\mathbb{Z}/n\mathbb{Z}$ generated by $k$. By a standard result, this subgroup has size $n / \gcd(n,k)$.</p>
<ul>
<li>When $\gcd(n,k) = 1$: orbit size $= n$. The traversal visits every vertex.</li>
<li>When $\gcd(n,k) = d > 1$: orbit size $= n/d$. The traversal visits only a fraction of the vertices.</li>
</ul>
<p>For prime $n$: $\gcd(n,k) = 1$ for every $1 \leq k \leq n-1$, without exception. <strong>Every traversal is complete.</strong> There is no step size that traps the path in a proper sub-orbit before visiting all vertices. This follows directly from the fact that a prime has no divisors other than 1 and itself, so $\mathbb{Z}/p\mathbb{Z}$ has no non-trivial subgroups (Lagrange&rsquo;s theorem: any subgroup of a group of prime order must have order 1 or $p$).</p>
<p>This is the specific property that makes 7 — and any prime — rhythmically fertile.</p>
<h2 id="the-contrast-with-six">The Contrast with Six</h2>
<p>The comparison with $n = 6$ is the clearest illustration.</p>
<p>In $\mathbb{Z}/6\mathbb{Z}$, the possible step sizes are 1, 2, 3, 4, 5. Their orbits:</p>
<table>
  <thead>
      <tr>
          <th>Step $k$</th>
          <th>$\gcd(6,k)$</th>
          <th>Orbit size</th>
          <th>Vertices visited</th>
      </tr>
  </thead>
  <tbody>
      <tr>
          <td>1</td>
          <td>1</td>
          <td>6</td>
          <td>0,1,2,3,4,5 (the hexagon)</td>
      </tr>
      <tr>
          <td>2</td>
          <td>2</td>
          <td>3</td>
          <td>0,2,4 only</td>
      </tr>
      <tr>
          <td>3</td>
          <td>3</td>
          <td>2</td>
          <td>0,3 only</td>
      </tr>
      <tr>
          <td>4</td>
          <td>2</td>
          <td>3</td>
          <td>0,2,4 only</td>
      </tr>
      <tr>
          <td>5</td>
          <td>1</td>
          <td>6</td>
          <td>0,5,4,3,2,1 (the hexagon reversed)</td>
      </tr>
  </tbody>
</table>
<p>The only step sizes that visit all six vertices are 1 and 5 — both of which just traverse the hexagon itself, not a star. Every non-trivial star polygon on six points gets trapped. $\{6/2\}$ visits only half the vertices. $\{6/3\}$ visits only two. There is no connected six-pointed star that isn&rsquo;t either the hexagon or a compound figure.</p>
<p>In $\mathbb{Z}/7\mathbb{Z}$, every step from 2 to 5 generates the full group:</p>
<table>
  <thead>
      <tr>
          <th>Step $k$</th>
          <th>$\gcd(7,k)$</th>
          <th>Orbit size</th>
          <th>Traversal</th>
      </tr>
  </thead>
  <tbody>
      <tr>
          <td>2</td>
          <td>1</td>
          <td>7</td>
          <td>1,3,5,7,2,4,6</td>
      </tr>
      <tr>
          <td>3</td>
          <td>1</td>
          <td>7</td>
          <td>1,4,7,3,6,2,5</td>
      </tr>
      <tr>
          <td>4</td>
          <td>1</td>
          <td>7</td>
          <td>1,5,2,6,3,7,4</td>
      </tr>
      <tr>
          <td>5</td>
          <td>1</td>
          <td>7</td>
          <td>1,6,4,2,7,5,3</td>
      </tr>
  </tbody>
</table>
<p>All four non-trivial step sizes give connected traversals. Both are stars. Both visit every vertex. This is not a coincidence: it is the algebraic signature of primality.</p>
<h2 id="from-geometry-to-rhythm">From Geometry to Rhythm</h2>
<p>The connection to drumming is direct. Here is the mechanism.</p>
<p>Consider a repeating rhythmic figure of 7 beats — a bar of 7/8, say, with positions 1 through 7. An <a href="/posts/euclidean-rhythms/">earlier post</a> discussed Euclidean rhythms: the algorithm that distributes $k$ onset positions as evenly as possible among $n$ slots. That is a problem of <em>selection</em> — which of the $n$ positions to activate.</p>
<p>The star polygon traversal asks a different question. Given that all $n$ positions are present, in what <em>order of emphasis</em> should they be related, such that each accent is a fixed distance from the last? The traversal of $\{n/k\}$ answers this: accent position $1$, then $1+k$, then $1+2k$, and so on modulo $n$.</p>
<p>For $\{7/2\}$: the accent cycle within a single bar runs $1 \to 3 \to 5 \to 7 \to 2 \to 4 \to 6$. Each featured beat is two positions ahead of the last.</p>
<p>Now project this across multiple bars. In bar 1, the primary accent sits on beat 1. In bar 2, if the accent shifts by 2, it lands on beat 3. Bar 3: beat 5. Bar 4: beat 7. Bar 5: beat 2. Bar 6: beat 4. Bar 7: beat 6. Bar 8: beat 1 again.</p>
<p>The accent takes <strong>seven bars</strong> to return to its starting position. Because $\gcd(2,7) = 1$, the step of 2 generates all of $\mathbb{Z}/7\mathbb{Z}$: every beat position receives the accent exactly once before the cycle resets. The resulting large-scale figure is $7 \times 7 = 49$ beats long — a super-phrase built from a single local rule.</p>
<p>The $\{7/3\}$ traversal generates the same exhaustiveness with a different path. Step 3 gives $1 \to 4 \to 7 \to 3 \to 6 \to 2 \to 5$: a seven-bar accent cycle that visits every position before repeating, but with wider spacing between accented beats, creating a different feel over the same underlying meter.</p>
<p>A six-beat figure with step 2 cannot do this. The accent visits only beats 1, 3, 5 — half the cycle — and loops back without touching beats 2, 4, 6. A drummer building phrase-level architecture from a six-beat grid is working with a more fragmented material.</p>
<h2 id="two-problems-one-prime">Two Problems, One Prime</h2>
<p>It is worth stating the relationship between the star polygon approach and Euclidean rhythms precisely, because the two are sometimes conflated <a href="#ref-2">[2]</a>.</p>
<p>The Euclidean algorithm distributes $k$ onsets among $n$ positions with maximal evenness. The result is a <em>subset</em> of the $n$ positions — a selection. The primality of $n$ matters here too: because $\gcd(k,p) = 1$ for prime $p$ and any $1 \leq k \leq p-1$, the Euclidean rhythm $E(k,p)$ always achieves its theoretical maximum of evenness. There are no divisibility shortcuts that cause clumping.</p>
<p>The star polygon traversal selects <em>no subset</em> — it relates all $n$ positions via a cyclic permutation. The primality of $n$ matters here because it guarantees that every non-trivial cyclic permutation (every step size $k$ with $1 < k < n$) generates the full group, visiting all positions before repeating.</p>
<p>Same arithmetic property — $\gcd(k,p) = 1$ for all non-zero $k$ — but the two problems ask different things of it. Euclidean rhythms use it to guarantee dense coverage. Star polygon traversals use it to guarantee no sub-orbit trapping.</p>
<h2 id="the-compound-structure">The Compound Structure</h2>
<p>Written out explicitly, the $\{7/2\}$ accent pattern over seven bars looks like this — with bold marking the featured beat in each bar:</p>
$$\begin{array}{rccccccc}
\text{bar 1:} & \mathbf{1} & 2 & 3 & 4 & 5 & 6 & 7 \\
\text{bar 2:} & 1 & 2 & \mathbf{3} & 4 & 5 & 6 & 7 \\
\text{bar 3:} & 1 & 2 & 3 & 4 & \mathbf{5} & 6 & 7 \\
\text{bar 4:} & 1 & 2 & 3 & 4 & 5 & 6 & \mathbf{7} \\
\text{bar 5:} & 1 & \mathbf{2} & 3 & 4 & 5 & 6 & 7 \\
\text{bar 6:} & 1 & 2 & 3 & \mathbf{4} & 5 & 6 & 7 \\
\text{bar 7:} & 1 & 2 & 3 & 4 & 5 & \mathbf{6} & 7 \\
\end{array}$$<p>Each bar is metrically identical. The large-scale accent — which beat carries the phrase-level emphasis — traces the traversal path of the $\{7/2\}$ star polygon across the seven-bar cycle.</p>
<p>This is the kind of large-scale rhythmic architecture visible in a great deal of Tool&rsquo;s output. Whether Danny Carey explicitly constructs accent cycles from star polygon traversal paths, or whether the same structure emerges from his intuitive sense of how prime time signatures behave, produces the same result. The mathematics and the musical instinct point toward the same pattern.</p>
<h2 id="why-the-heptagram">Why the Heptagram</h2>
<p>The full mathematical picture of why seven-fold symmetry is special — why the regular heptagon cannot be constructed by compass and straightedge, what the minimal polynomial of $\cos(2\pi/7)$ implies about the heptagon&rsquo;s position outside the constructible world, and how the Galois group of the cyclotomic field over $\mathbb{Q}$ carries the obstruction — is developed in the companion post <a href="/posts/tool-impossible-heptagon/">The Impossible Heptagon</a>.</p>
<p>The short version, for the purposes of this post: seven is the smallest odd prime that is not a Fermat prime ($2^{2^j}+1$). This algebraic accident places it outside the reach of ruler-and-compass construction — the heptagon exists as an ideal but cannot be manifested by the classical tools. Its star polygons are the accessible shadows of an inaccessible form. And its primality, in both the constructibility sense and the traversal sense, is precisely what makes it inexhaustible as a rhythmic resource.</p>
<p>The Fibonacci structure in &ldquo;Lateralus&rdquo; <a href="#ref-3">[3]</a>, the group theory underlying twelve-tone equal temperament <a href="#ref-4">[4]</a>, and the Euclidean rhythm algorithm <a href="#ref-5">[5]</a> are all different facets of the same observation: mathematical structure, introduced as compositional constraint, generates musical complexity that cannot easily be produced by intuition alone. The star polygon is another instance. The drummer who keeps a heptagram on his kit has found, by a non-mathematical route, an object with a precise and interesting mathematical identity.</p>
<h2 id="references">References</h2>
<p><span id="ref-1"></span>[1] Coxeter, H.S.M. (1973). <em>Regular Polytopes</em> (3rd ed.). Dover. Ch. 2.</p>
<p><span id="ref-2"></span>[2] Toussaint, G. (2013). <em>The Geometry of Musical Rhythm: What Makes a &ldquo;Good&rdquo; Rhythm Good?</em> CRC Press.</p>
<p><span id="ref-3"></span>[3] See <a href="/posts/fibonacci-lateralus/">Fibonacci and Lateralus</a> on this blog.</p>
<p><span id="ref-4"></span>[4] See <a href="/posts/twelve-tet-group-theory-musical-tuning/">Twelve-TET and Group Theory</a> on this blog.</p>
<p><span id="ref-5"></span>[5] See <a href="/posts/euclidean-rhythms/">Euclidean Rhythms</a> on this blog.</p>
]]></content:encoded>
    </item>
    <item>
      <title>The Impossible Heptagon</title>
      <link>https://sebastianspicker.github.io/posts/tool-impossible-heptagon/</link>
      <pubDate>Mon, 15 Jan 2024 00:00:00 +0000</pubDate>
      <guid>https://sebastianspicker.github.io/posts/tool-impossible-heptagon/</guid>
      <description>Danny Carey calls it sacred geometry. Gauss proved it non-constructible. They are, unexpectedly, describing the same object.</description>
      <content:encoded><![CDATA[<p>Danny Carey — drummer of Tool, one of the most rhythmically inventive musicians in rock — keeps a seven-pointed star on his kit and speaks about it using the language of sacred geometry. The heptagram appears in Tool&rsquo;s visual artwork, in the Thelemic symbolism Carey draws on, in pre-modern cosmological diagrams, and in the decorative traditions of several cultures that had no contact with each other. The claim, loosely stated, is that seven-fold symmetry is privileged: that it reflects something structurally true, that its forms carry significance beyond the aesthetic.</p>
<p>The scientific reflex here is usually impatience. &ldquo;Sacred geometry&rdquo; occupies an uncomfortable cultural space — mathematically dressed, factually thin, reliant on the listener not checking claims too carefully. The golden ratio does not appear everywhere in nature. Most things described as sacred in this tradition are better described as things the speaker found surprising before learning a more precise vocabulary.</p>
<p>But the heptagon is genuinely strange. Not for the reasons usually given. For a different reason — a theorem.</p>
<p><strong>The regular heptagon cannot be constructed with compass and straightedge.</strong></p>
<p>Not &ldquo;it is difficult.&rdquo; Not &ldquo;no one has found a construction yet.&rdquo; The regular seven-sided polygon — all sides equal, all interior angles equal — is <em>provably impossible</em> to construct using an unmarked ruler and compass in finitely many steps. This has been known since 1801.</p>
<h2 id="the-classical-constraint">The Classical Constraint</h2>
<p>Greek geometry restricted its tools deliberately. An unmarked straightedge draws lines through two known points. A compass draws circles centred at a known point with a given radius. No angle trisection. No markings. No graduated instruments. Just these two operations, applied one at a time, finitely many times.</p>
<p>Within this constraint, a great deal is achievable. A perpendicular bisector. An equilateral triangle. A regular pentagon — which requires the golden ratio and takes some work, but is reachable. A regular hexagon (trivially: six equilateral triangles around a centre).</p>
<p>Then: nothing for the heptagon. Greek geometers left no construction. Medieval Islamic mathematicians, who knew the regular polygon problem well, left no construction. Albrecht Dürer, in his 1525 <em>Underweysung der Messung</em>, gave an approximate construction that falls short by a small but nonzero margin. Each generation encountered the same wall.</p>
<p>In 1796, an 18-year-old Gauss proved that the regular 17-gon <em>is</em> constructible — a result so unexpected that he reportedly decided at that moment to become a mathematician rather than a philologist. In his 1801 <em>Disquisitiones Arithmeticae</em> he gave the complete characterisation of which regular polygons are constructible and which are not <a href="#ref-1">[1]</a>. The heptagon was definitively placed among the impossible.</p>
<h2 id="gausss-theorem">Gauss&rsquo;s Theorem</h2>
<p>A regular $n$-gon is constructible with compass and straightedge if and only if $n$ has the form</p>
$$n = 2^k \cdot p_1 \cdot p_2 \cdots p_m$$<p>where $k \geq 0$ and the $p_i$ are distinct <strong>Fermat primes</strong> — primes of the form $2^{2^j} + 1$.</p>
<p>The Fermat primes currently known:</p>
<table>
  <thead>
      <tr>
          <th>$j$</th>
          <th>$F_j = 2^{2^j}+1$</th>
          <th>Prime?</th>
      </tr>
  </thead>
  <tbody>
      <tr>
          <td>0</td>
          <td>3</td>
          <td>✓</td>
      </tr>
      <tr>
          <td>1</td>
          <td>5</td>
          <td>✓</td>
      </tr>
      <tr>
          <td>2</td>
          <td>17</td>
          <td>✓</td>
      </tr>
      <tr>
          <td>3</td>
          <td>257</td>
          <td>✓</td>
      </tr>
      <tr>
          <td>4</td>
          <td>65537</td>
          <td>✓</td>
      </tr>
      <tr>
          <td>5</td>
          <td>4 294 967 297</td>
          <td>✗ (Euler, 1732)</td>
      </tr>
      <tr>
          <td>6</td>
          <td>18 446 744 073 709 551 617</td>
          <td>✗</td>
      </tr>
      <tr>
          <td>⋮</td>
          <td>⋮</td>
          <td>no further Fermat primes known</td>
      </tr>
  </tbody>
</table>
<p>Five Fermat primes are known, all identified by the seventeenth century. Fermat himself conjectured that all numbers of this form are prime; he was wrong from $j = 5$ onward. Whether any further Fermat primes exist remains an open problem.</p>
<p>The constructible regular polygons therefore include the triangle (3), square (4), pentagon (5), hexagon (6), octagon (8), decagon (10), 15-gon, 17-gon, 257-gon, 65537-gon, and products of these with powers of 2. The 65537-gon was actually fully constructed by Johann Gustav Hermes, who spent around ten years on the computation in the 1880s and deposited a manuscript reportedly filling a large trunk at the University of Göttingen, where it remains.</p>
<p>Seven is prime, but $7 \neq 2^{2^j} + 1$ for any $j$ — it is not a Fermat prime. Therefore the regular heptagon is not on the list. It is not constructible.</p>
<h2 id="the-algebra-behind-the-geometry">The Algebra Behind the Geometry</h2>
<p>Why does the structure of Fermat primes determine constructibility? The connection goes through algebra <a href="#ref-2">[2]</a><a href="#ref-3">[3]</a>.</p>
<p>Every compass-and-straightedge construction corresponds to solving a sequence of equations of degree at most 2. Bisecting an angle, finding an intersection of a line and a circle — each step is a quadratic operation. After $k$ such steps, the numbers reachable lie in some field extension of $\mathbb{Q}$ (the rationals) with degree over $\mathbb{Q}$ at most $2^k$. Constructibility therefore requires the degree of the relevant extension to be a power of 2.</p>
<p>To construct a regular $n$-gon, you need to construct the angle $2\pi/n$, which requires constructing $\cos(2\pi/n)$. The question is: over what kind of field extension does $\cos(2\pi/n)$ sit?</p>
<p>For $n = 7$: let $\omega = e^{2\pi i/7}$, a primitive 7th root of unity. The minimal polynomial of $\omega$ over $\mathbb{Q}$ is the 7th cyclotomic polynomial</p>
$$\Phi_7(x) = x^6 + x^5 + x^4 + x^3 + x^2 + x + 1,$$<p>which is irreducible over $\mathbb{Q}$, giving $[\mathbb{Q}(\omega) : \mathbb{Q}] = 6$. Since $\cos(2\pi/7) = (\omega + \omega^{-1})/2$, and since $\omega$ satisfies a degree-2 polynomial over $\mathbb{Q}(\cos 2\pi/7)$, we get</p>
$$[\mathbb{Q}(\cos 2\pi/7) : \mathbb{Q}] = 3.$$<p>Specifically, $c = \cos(2\pi/7)$ is the root of the irreducible cubic</p>
$$8c^3 + 4c^2 - 4c - 1 = 0,$$<p>or equivalently, $\alpha = 2\cos(2\pi/7)$ satisfies</p>
$$\alpha^3 + \alpha^2 - 2\alpha - 1 = 0.$$<p>The three roots of this cubic are $2\cos(2\pi/7)$, $2\cos(4\pi/7)$, and $2\cos(6\pi/7)$. By Vieta&rsquo;s formulas their sum is $-1$ and their product is $1$ — which can be verified directly from the identity $\cos(2\pi/7) + \cos(4\pi/7) + \cos(6\pi/7) = -1/2$.</p>
<p>The degree of the extension is 3. Three is not a power of 2. Therefore $\cos(2\pi/7)$ cannot be reached by any tower of quadratic extensions of $\mathbb{Q}$. Therefore the regular heptagon is not constructible. $\square$</p>
<p>Compare the pentagon: $\cos(2\pi/5) = (\sqrt{5}-1)/4$, satisfying the quadratic $4x^2 + 2x - 1 = 0$. Degree 2 — a power of 2. Constructible.</p>
<p>The 17-gon: the Galois group of $\mathbb{Q}(\zeta_{17})/\mathbb{Q}$ is $(\mathbb{Z}/17\mathbb{Z})^* \cong \mathbb{Z}/16\mathbb{Z}$, order $16 = 2^4$. The extension decomposes into four quadratic steps. This is exactly what Gauss computed at 18.</p>
<p>For 7: $(\mathbb{Z}/7\mathbb{Z})^* \cong \mathbb{Z}/6\mathbb{Z}$, order $6 = 2 \times 3$. The factor of 3 is the obstruction. The Galois group is not a 2-group, so the extension cannot be decomposed into quadratic steps. The heptagon is out of reach.</p>
<h2 id="sacred-precisely">Sacred, Precisely</h2>
<p>The phrase &ldquo;sacred geometry&rdquo; usually does work that &ldquo;elegant mathematics&rdquo; could do more honestly. But the heptagon is a case where something with genuine mathematical content sits underneath the mystical framing.</p>
<p>The Platonic tradition held that certain geometric forms exist as ideals — perfect, unchanging, more real than their physical approximations. The philosopher&rsquo;s claim is that the heptagon exists in a realm beyond its material instantiation. The mathematician&rsquo;s claim is: the heptagon is perfectly well-defined — seven equal sides, seven equal angles — but it cannot be reached from $\mathbb{Q}$ by the operations available to ruler and compass. You can approximate it to any desired precision. You can construct it exactly using origami, which allows angle trisection and is strictly more powerful than compass and straightedge <a href="#ref-4">[4]</a>. But the classical constructive program — the one that reaches the pentagon, the hexagon, the 17-gon, the 65537-gon — cannot reach the heptagon.</p>
<p>There is a precise mathematical sense in which it lies outside the constructible world. Whether that constitutes sacredness is a question for a different kind of argument. But it is not nothing. The Pythagoreans were working without Galois theory; they had an intuition without the theorem. The theorem, when it came, confirmed that intuition about seven while explaining it more clearly than they could.</p>
<p>Carey&rsquo;s intuition — that 7 sits outside the ordinary — is, by this route, formally correct.</p>
<h2 id="what-the-heptagram-is">What the Heptagram Is</h2>
<p>The regular heptagon may be impossible to construct exactly, but the heptagram — the seven-pointed star — is perfectly drawable. Connecting every second vertex of an approximate regular heptagon gives $\{7/2\}$ in Schläfli notation <a href="#ref-5">[5]</a>; connecting every third vertex gives $\{7/3\}$. Both are closed figures. Both appear throughout pre-modern symbolic traditions, which is unsurprising: they are the most intricate star polygons drawable with a single pen stroke before complexity outruns visibility.</p>
<p>They are also generators of rhythmic structure. Because 7 is prime, every star polygon on seven points visits all seven vertices in a single closed traversal — a property that does not hold for six-pointed or eight-pointed stars. This turns out to matter for how drum patterns are built across multiple bars. That connection — from the primality of 7 to the architecture of rhythmic accent cycles — is the subject of the companion post, <a href="/posts/tool-star-polygons-drum-machines/">Star Polygons and Drum Machines</a>.</p>
<p>The broader series on mathematics in Tool&rsquo;s music began with the Fibonacci structure embedded in the time signatures and syllable counts of &ldquo;Lateralus&rdquo; <a href="#ref-6">[6]</a>, and the group-theoretic structure underlying twelve-tone equal temperament provides the same algebraic scaffolding seen here <a href="#ref-7">[7]</a>.</p>
<h2 id="references">References</h2>
<p><span id="ref-1"></span>[1] Gauss, C.F. (1801). <em>Disquisitiones Arithmeticae</em>. Leipzig: Fleischer. (§VII.)</p>
<p><span id="ref-2"></span>[2] Stewart, I. (2004). <em>Galois Theory</em> (3rd ed.). CRC Press. Ch. 4.</p>
<p><span id="ref-3"></span>[3] Conway, J.H. &amp; Guy, R.K. (1996). <em>The Book of Numbers</em>. Springer. pp. 190–202.</p>
<p><span id="ref-4"></span>[4] Hull, T. (2011). Solving cubics with creases: The work of Beloch and Lill. <em>The American Mathematical Monthly</em>, 118(4), 307–315. <a href="https://doi.org/10.4169/amer.math.monthly.118.04.307">DOI: 10.4169/amer.math.monthly.118.04.307</a></p>
<p><span id="ref-5"></span>[5] Coxeter, H.S.M. (1973). <em>Regular Polytopes</em> (3rd ed.). Dover. Ch. 2.</p>
<p><span id="ref-6"></span>[6] See <a href="/posts/fibonacci-lateralus/">Fibonacci and Lateralus</a> on this blog.</p>
<p><span id="ref-7"></span>[7] See <a href="/posts/twelve-tet-group-theory-musical-tuning/">Twelve-TET and Group Theory</a> on this blog.</p>
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      <title>Spiral Out: Tool&#39;s Lateralus, the Fibonacci Sequence, and the Mathematics of Musical Structure</title>
      <link>https://sebastianspicker.github.io/posts/fibonacci-lateralus/</link>
      <pubDate>Tue, 08 Nov 2022 00:00:00 +0000</pubDate>
      <guid>https://sebastianspicker.github.io/posts/fibonacci-lateralus/</guid>
      <description>Alongside physics and astronomy, two other things have occupied an unreasonable share of my attention since adolescence: mathematics and music. Lateralus by Tool — released 2001, still in rotation — is the piece that most conspicuously occupies the intersection. The song is structurally built around the Fibonacci sequence, from the syllable counts in Maynard Keenan&amp;rsquo;s vocals to the time signature pattern that concatenates to F(16). This post works through the mathematics in some detail and asks why it works musically.</description>
      <content:encoded><![CDATA[<h2 id="two-passions-one-song">Two Passions, One Song</h2>
<p>Physics training means coming to mathematics as a tool before arriving at it as
an object of aesthetic interest, and it
took me longer than it should have to notice that a proof can be
beautiful in the same way a piece of music can be beautiful — not
despite its rigour but because of it. Both reward attention to
structure. Both have surfaces accessible to a casual listener and depths
that only reveal themselves when you look harder.</p>
<p>Lateralus, the title track of Tool&rsquo;s 2001 album, is a convenient case
study for the overlap. It is not the only piece of music built around
Fibonacci numbers — Bartók made the connection decades earlier, and it
appears in scattered places across Western and non-Western traditions —
but it is among the most thoroughly and deliberately constructed, and
the mathematical structure is audible rather than merely theoretical.</p>
<p>What follows is an attempt to do justice to both dimensions: the
mathematics of the Fibonacci sequence and the golden ratio, and the
musical mechanics of how those structures show up and what they do.</p>
<hr>
<h2 id="the-fibonacci-sequence">The Fibonacci Sequence</h2>
<p>The sequence is defined by a recurrence relation. Starting from the
initial values $F(1) = 1$ and $F(2) = 1$, each subsequent term is the
sum of the two preceding ones:</p>
$$F(n) = F(n-1) + F(n-2), \quad n \geq 3$$<p>This gives:</p>
$$1,\; 1,\; 2,\; 3,\; 5,\; 8,\; 13,\; 21,\; 34,\; 55,\; 89,\; 144,\; 233,\; 377,\; 610,\; \mathbf{987},\; 1597,\; \ldots$$<p>The term $987$ is the sixteenth Fibonacci number, $F(16)$. Keep that
in mind.</p>
<p>The recurrence can be encoded compactly in a matrix formulation. For
$n \geq 1$:</p>
$$\begin{pmatrix} F(n+1) \\ F(n) \end{pmatrix} = \begin{pmatrix} 1 & 1 \\ 1 & 0 \end{pmatrix}^n \begin{pmatrix} 1 \\ 0 \end{pmatrix}$$<p>This is more than notational tidiness — it connects the Fibonacci
sequence to the eigenvalues of the matrix
$\mathbf{A} = \bigl(\begin{smallmatrix}1 & 1 \\ 1 & 0\end{smallmatrix}\bigr)$,
which are exactly $\varphi$ and $-1/\varphi$ where $\varphi$ is the
golden ratio. That connection gives us Binet&rsquo;s formula, a closed-form
expression for the $n$-th Fibonacci number:</p>
$$F(n) = \frac{\varphi^n - \psi^n}{\sqrt{5}}, \quad \varphi = \frac{1+\sqrt{5}}{2},\quad \psi = \frac{1-\sqrt{5}}{2} = -\frac{1}{\varphi}$$<p>Since $|\psi| < 1$, the term $\psi^n / \sqrt{5}$ diminishes rapidly,
and for large $n$ we have the convenient approximation:</p>
$$F(n) \approx \frac{\varphi^n}{\sqrt{5}}$$<p>This means Fibonacci numbers grow <em>exponentially</em>, at a rate governed by
the golden ratio. The sequence does not grow linearly or polynomially; it
spirals outward.</p>
<hr>
<h2 id="the-golden-ratio">The Golden Ratio</h2>
<p>The golden ratio $\varphi$ appears as the limit of consecutive Fibonacci
ratios:</p>
$$\varphi = \lim_{n \to \infty} \frac{F(n+1)}{F(n)} = \frac{1+\sqrt{5}}{2} \approx 1.61803\ldots$$<p>It can be derived from a simple geometric proportion: divide a line
segment into two parts such that the ratio of the whole segment to the
longer part equals the ratio of the longer part to the shorter part.
Calling those ratios $r$:</p>
$$\frac{a+b}{a} = \frac{a}{b} = r \implies r^2 - r - 1 = 0 \implies r = \frac{1+\sqrt{5}}{2} = \varphi$$<p>What makes $\varphi$ mathematically distinctive is its continued fraction
representation:</p>
$$\varphi = 1 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{1 + \cdots}}}$$<p>This is the simplest possible infinite continued fraction. It is also, in
a precise sense, the <em>hardest</em> real number to approximate by rational
fractions. The convergents of a continued fraction are the best rational
approximations to a real number at each level of precision; the
convergents of $\varphi$ are exactly the ratios of consecutive Fibonacci
numbers: $1/1$, $2/1$, $3/2$, $5/3$, $8/5$, $13/8$, $\ldots$ These
converge more slowly to $\varphi$ than the convergents of any other
irrational number. $\varphi$ is, in this sense, maximally irrational.</p>
<p>That property has a physical consequence. In botanical phyllotaxis — the
arrangement of leaves, seeds, and petals on plants — structures that grow
by adding new elements at a fixed angular increment will pack most
efficiently when that increment is as far as possible from any rational
fraction of a full rotation. The optimal angle is:</p>
$$\theta = \frac{2\pi}{\varphi^2} \approx 137.508°$$<p>This is the <em>golden angle</em>, and it is the reason sunflower seed spirals
count $55$ and $89$ (consecutive Fibonacci numbers) in their two
counter-rotating sets. The mathematics of efficient growth in nature
and the mathematics of the Fibonacci sequence are the same mathematics.</p>
<p>The golden spiral — the logarithmic spiral whose growth factor per
quarter turn is $\varphi$ — is the visual representation of this: it
is self-similar, expanding without bound while maintaining constant
proportionality.</p>
<hr>
<h2 id="fibonacci-numbers-in-music-before-tool">Fibonacci Numbers in Music: Before Tool</h2>
<p>The connection between the Fibonacci sequence and musical structure is
not Tool&rsquo;s invention. The most carefully documented case is Béla
Bartók, whose Music for Strings, Percussion and Celesta (1936) has been
analysed exhaustively by Ernő Lendvai. In the first movement, the
climax arrives at bar 55 (a Fibonacci number), and Lendvai counted the
overall structure as 89 bars — the score has 88, but he added an implied
final rest bar to reach the Fibonacci number — dividing at bar 55 with
near-mathematical precision. Lendvai argued that Bartók consciously embedded Fibonacci
proportions into formal structure, tonal architecture, and thematic
development throughout much of his output.</p>
<p>Whether these proportions were conscious design or an instinct that
selected naturally resonant proportions is contested. The same question
applies to claims about Mozart and Chopin. What is more defensible is
a structural observation about the piano keyboard and Western scales
that requires no attribution of intent:</p>
<p>A single octave on the piano keyboard has <strong>13 keys</strong>, comprising <strong>8
white keys</strong> and <strong>5 black keys</strong>. The black keys are grouped as <strong>2</strong>
and <strong>3</strong>. The numbers $2, 3, 5, 8, 13$ are five consecutive Fibonacci
numbers — $F(3)$ through $F(7)$.</p>
<p>The standard Western scales make this concrete. The major scale
contains <strong>7 distinct pitches</strong> within an octave of <strong>12 semitones</strong>.
The pentatonic scale (ubiquitous in folk, blues, rock) contains <strong>5</strong>
pitches. The chromatic scale contains <strong>12</strong> pitch classes per octave;
counting both endpoints of the octave (C to C) gives <strong>13</strong> chromatic
notes, the next Fibonacci number.</p>
<p>Harmonic intervals in just intonation are rational approximations of
simple frequency ratios: the octave (2:1), the perfect fifth (3:2),
the perfect fourth (4:3), the major third (5:4), the minor third (6:5).
The numerators and denominators are small integers, often Fibonacci
numbers or their neighbours. The major triad — the structural foundation
of tonal Western music — consists of intervals in frequency ratios
$4:5:6$, three consecutive integers that bracket the Fibonacci-adjacent
range.</p>
<p>This does not mean that Western music is secretly Fibonacci. It means
that the integer frequency ratios that produce consonant intervals are
the small integers, and small integers include the small Fibonacci
numbers. The connection is genuine but not exclusive.</p>
<hr>
<h2 id="lateralus">Lateralus</h2>
<p>Tool&rsquo;s <em>Lateralus</em> (2001, album of the same name) is unusual in that
the Fibonacci construction is not an analytical inference applied after
the fact — it was discussed publicly by the band. Drummer Danny Carey has
spoken about his engagement with sacred geometry and mathematical
structure, and the song&rsquo;s construction has been described as intentional
by multiple band members.</p>
<p>There are two primary levels of Fibonacci structure in the song. The
third — the thematic content of the lyrics — makes the mathematical
frame explicit.</p>
<h3 id="the-syllable-count">The Syllable Count</h3>
<p>The opening verses are constructed so that successive lines contain
syllable counts following the Fibonacci sequence ascending:
$1, 1, 2, 3, 5, 8, 13$. The first syllable count is a single word.
The second is another. The third is a two-syllable phrase. The sequence
continues, each line adding the weight of the previous two, until the
thirteenth-syllable line, which in structure and delivery feels like the
crest of a wave.</p>
<p>The second half of the verse then descends: $13, 8, 5, 3, 2, 1, 1$.
Or, in some analyses, the chorus and pre-chorus sections begin a new
ascending Fibonacci run before the full descent, creating a nested
structure of expansions and contractions.</p>
<p>The audible effect of this design is not arbitrary. A sequence of lines
whose syllable counts follow $1, 1, 2, 3, 5, 8, 13$ creates a
consistently accelerating density of text over the same musical time.
The vocal line becomes more compressed as the syllable count rises,
building tension — and then the descent releases it. This is not how
most pop or rock lyrics are structured. It produces a breathing,
organic quality, the way a plant reaches toward light.</p>
<h3 id="the-time-signature-987">The Time Signature: 987</h3>
<p>The verse sections of the song cycle through three time signatures in
succession: $9/8$, then $8/8$, then $7/8$.</p>
$$9/8 + 8/8 + 7/8$$<p>This three-bar pattern repeats. Now: the sequence of numerators is $9$,
$8$, $7$. Written as a three-digit number: <strong>987</strong>. And as noted above,
$987 = F(16)$, the sixteenth Fibonacci number.</p>
<p>Whether this is a deliberate encoding or a remarkable coincidence is a
matter of interpretation. The time signature sequence is definitely
deliberate — asymmetric meters of this kind require careful compositional
choice. The fact that their numerators concatenate to a Fibonacci number
is either intentional and clever or accidental and still remarkable.
Either way, the time signature pattern has a musical function independent
of the Fibonacci reading.</p>
<p>In standard rock, time is almost always $4/4$: four even beats per bar,
a pulse that is maximally predictable and maximally amenable to groove.
The $9/8 + 8/8 + 7/8$ pattern is the opposite. Each bar has a different
length. The listener&rsquo;s internal metronome, calibrated to $4/4$, cannot
lock onto the pattern. The music generates forward momentum not through
a repeated downbeat but through the continuous, non-periodic unfolding
of measures whose lengths shift. This is the rhythmic analogue of a
spiral: no two revolutions are identical in length, but the growth is
consistent.</p>
<p>The chorus and other sections use different time signatures, including
stretches in $5/8$ and $7/8$ — Fibonacci numbers again, and specifically
the $5, 8, 13$ triplet that appears so often in this context.</p>
<h3 id="the-thematic-content">The Thematic Content</h3>
<p>The lyrics are explicitly about spirals, Fibonacci growth, and the
experience of reaching beyond a current state of development. They
reference the idea of expanding one&rsquo;s perception outward through
accumulating cycles, each containing and exceeding the previous one.
The chorus refrain — about spiralling outward — names the mathematical
structure of the golden spiral directly. The song is, in its own terms,
about the process that the mathematics describes.</p>
<p>This kind of thematic coherence between structure and content is what
makes the construction interesting rather than merely clever. The
Fibonacci structure is not decorative. It is the argument of the song
made manifest in its form.</p>
<hr>
<h2 id="why-fibonacci-structure-works-in-music">Why Fibonacci Structure Works in Music</h2>
<p>The most interesting question is not whether the Fibonacci structure is
there — it clearly is — but why it produces the musical effect it does.</p>
<p>Consider what the Fibonacci sequence represents physically. It is the
growth law of structures that build on their own preceding state:
$F(n) = F(n-1) + F(n-2)$. Unlike arithmetic growth (add a constant)
or geometric growth (multiply by a constant), Fibonacci growth is
<em>self-referential</em>. Each term contains the memory of the previous two.
The sequence is expansive but not uniform; it accelerates, but always
in proportion to what came before.</p>
<p>Musical tension and release are, in an important sense, the same
mechanism. A phrase creates an expectation; its continuation either
confirms or subverts that expectation; resolution reduces the tension.
What makes a musical phrase feel like it is building toward something
is precisely the progressive accumulation of expectation — each bar
adding its weight to the previous, the accumulated tension requiring
resolution at a scale proportional to the build-up. The Fibonacci
syllable structure in Lateralus generates this literally: each line is
denser than the previous two lines&rsquo; combined syllable count would
suggest is comfortable, until the structure has to breathe.</p>
<p>The time signature asymmetry works similarly. In $4/4$, the beat is
predictable, and the listener&rsquo;s body can lock to it and then coast on
that lock. In $9/8 + 8/8 + 7/8$, the beat is never fully locked — the
pattern is periodic (it repeats) but the internal structure of each
repetition is shifting. The listener is perpetually catching up,
perpetually leaning slightly into the music to find the next downbeat.
This is not discomfort — it is engagement. The mathematical reason is
that the pattern is large enough to be periodic (it does repeat) but
small enough to be audible as a unit. The brain can learn the 24-beat
super-pattern; it just requires attention that $4/4$ does not.</p>
<p>There is a deeper reason why golden-ratio proportions feel right in
musical form. The golden section of a piece — the point at which the
piece divides in the $\varphi : 1$ ratio — is the point of maximum
accumulated development before the final resolution. In a five-minute
piece, the golden section falls at roughly 3:05. This is, empirically,
where the emotional and structural climax tends to sit in a wide range
of well-regarded music, from Baroque to jazz. Whether composers
consciously target this proportion or whether the proportion is what
accumulated development looks like when done well is not easily
separable. But the mathematical reason it is <em>a</em> proportion worth
targeting is that $\varphi$ is the only division point that is
self-similar: the ratio of the whole to the longer part equals the ratio
of the longer part to the shorter part. There is no arbitrary scale
associated with the golden section; it is scale-invariant, the same
proportion at every level of analysis.</p>
<hr>
<h2 id="a-brief-note-on-binet-and-limits">A Brief Note on Binet and Limits</h2>
<p>The closed-form expression for Fibonacci numbers,</p>
$$F(n) = \frac{\varphi^n - \psi^n}{\sqrt{5}},$$<p>has a pleasing consequence for large $n$. Since $|\psi| \approx 0.618 < 1$,
the term $\psi^n \to 0$, and $F(n)$ is simply the nearest integer to
$\varphi^n / \sqrt{5}$. The integers produced by the Fibonacci recurrence
are the integers that $\varphi^n / \sqrt{5}$ passes closest to. The
exponential growth of $\varphi^n$ and the rounding to integers together
give the sequence.</p>
<p>This is also why the ratios $F(n+1)/F(n)$ converge to $\varphi$
exponentially fast — the error is $\mathcal{O}(|\psi/\varphi|^n)
= \mathcal{O}(\varphi^{-2n})$ — and why, for musical purposes, the
Fibonacci ratios $8:5$, $13:8$, $21:13$ are already excellent
approximations of the golden ratio, close enough that the ear cannot
distinguish them from $\varphi$ in any direct sense.</p>
<hr>
<h2 id="what-lateralus-is">What Lateralus Is</h2>
<p><em>Lateralus</em> is not a math lecture set to music. It is a nine-minute
progressive metal track that is physically involving, rhythmically
complex, and lyrically coherent. The Fibonacci structure would be
worthless if the song were not also, on purely musical terms, good.</p>
<p>What the mathematics adds is a vocabulary for something the song achieves
anyway: the sense of growing without ever arriving, of each section being
both a resolution of what came before and an opening toward something
larger. The golden spiral does not end. The Fibonacci sequence does not
converge. The song does not resolve in the sense that a classical sonata
resolves; it spirals to a close.</p>
<p>The reason this is worth writing about is that it makes concrete a
connection that is usually stated vaguely: mathematics and music are
similar. They are similar in specific and articulable ways. The
self-referential structure of the Fibonacci recurrence, the scale-
invariance of the golden ratio, the information-theoretic account of
tension and expectation — these are not metaphors for musical experience.
They are, in this case, the actual mechanism.</p>
<hr>
<h2 id="references">References</h2>
<p>Lendvai, E. (1971). <em>Béla Bartók: An Analysis of His Music.</em> Kahn &amp;
Averill.</p>
<p>Benson, D. J. (2006). <em>Music: A Mathematical Offering.</em> Cambridge
University Press. <em>(For an introduction to the general theory of tuning,
temperament, and harmonic series.)</em></p>
<p>Tool. (2001). <em>Lateralus.</em> Volcano Records.</p>
<p>Livio, M. (2002). <em>The Golden Ratio: The Story of Phi, the World&rsquo;s Most
Astonishing Number.</em> Broadway Books.</p>
<p>Knott, R. (2013). Fibonacci numbers and the golden section in art,
architecture and music. <em>University of Surrey Mathematics Department.</em>
<a href="https://r-knott.surrey.ac.uk/Fibonacci/fibInArt.html">https://r-knott.surrey.ac.uk/Fibonacci/fibInArt.html</a></p>
<hr>
<h2 id="changelog">Changelog</h2>
<ul>
<li><strong>2025-11-20</strong>: Clarified the Bartók bar count: the written score has 88 bars; Lendvai&rsquo;s analysis counted 89 by adding an implied final rest bar to reach the Fibonacci number. Previously stated as &ldquo;89 bars&rdquo; without qualification.</li>
</ul>
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